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x^2-200x+1000=0
a = 1; b = -200; c = +1000;
Δ = b2-4ac
Δ = -2002-4·1·1000
Δ = 36000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36000}=\sqrt{3600*10}=\sqrt{3600}*\sqrt{10}=60\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-60\sqrt{10}}{2*1}=\frac{200-60\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+60\sqrt{10}}{2*1}=\frac{200+60\sqrt{10}}{2} $
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